Solve for x, given
Ax^2 + B|x| + C = 0, where A,B,C are all positive.
Ax^2 + B|x| + C = 0, where A,B,C are all positive.
JIGYASA
JIGYASA
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Quadratic Equation
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2 Re: Quadratic Equation Thu Mar 11, 2010 3:42 pm
arubuee
Case 1: When x>= 0
Equation becomes Ax^2 + Bx + C = 0
So x = (-B + sqrt(B^2 - 4AC))/ 2A and (-B - sqrt(B^2 - 4AC))/ 2A
Accept only those x which are x >= 0
Case 2: When x < 0
Equation becomes Ax^2 - Bx + C = 0
So x = (B + sqrt(B^2 - 4AC))/ 2A and (B - sqrt(B^2 - 4AC))/ 2A
Accept only those x which are x < 0
Equation becomes Ax^2 + Bx + C = 0
So x = (-B + sqrt(B^2 - 4AC))/ 2A and (-B - sqrt(B^2 - 4AC))/ 2A
Accept only those x which are x >= 0
Case 2: When x < 0
Equation becomes Ax^2 - Bx + C = 0
So x = (B + sqrt(B^2 - 4AC))/ 2A and (B - sqrt(B^2 - 4AC))/ 2A
Accept only those x which are x < 0
3 @arubuee Thu Mar 11, 2010 5:59 pm
Lucifer
Admin
well according to u the value of x depends on the values of A, B,C. Well actually it doesn't depend on the values A,B,C.
given A , B, C > 0, then
Ax^2 >=0 - (1)
B|x| >=0 - (2)
C > 0 -(3)
Adding 1,2 & 3, we get,
Ax^2 + B|x| + C > 0, therefore there is no real value of x for which
Ax^2 + B|x| + C=0
given A , B, C > 0, then
Ax^2 >=0 - (1)
B|x| >=0 - (2)
C > 0 -(3)
Adding 1,2 & 3, we get,
Ax^2 + B|x| + C > 0, therefore there is no real value of x for which
Ax^2 + B|x| + C=0
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